Question

})=2" alt="6\sqrt{3}+2(1-\sqrt{27})=2" align="absmiddle" class="latex-formula">
Need step by step

Answer 1

$6\sqrt{3}+2-2\sqrt{27} = 2$

$6\sqrt{3}+2-2\sqrt{3\cdot 9} = 2$

$6\sqrt{3}+2-2\cdot\sqrt{3}\cdot \sqrt{9}=2$

$6\sqrt{3}+2-2\cdot \sqrt{3}\cdot 3=2$

$6\sqrt{3}+2-6\sqrt{3}=2$

$2=2$

Answer 2

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...