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pshichka [43]
3 years ago
9

Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reactio

n:
Ni2+(aq) + Cu(s) ---> Ni(s) + Cu2+(aq)
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm.
Equilibrium constant: __________ delta G° for this reaction would be _________ ( greater /less ) than zero.
What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cu2+ concentration is 4.38×10-4 M and the Al3+concentration is 1.08 M ?
3Cu2+(aq) + 2Al(s)----> 3Cu(s) + 2Al3+(aq)
Chemistry
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

Check the explanation

Explanation:

cell CuE Ecell 0.337 (-0.14) Ecl0.477 V

Since E^o_{ cell } > 0 , the value of \Delta G^o will be negative.

\Delta G^o < 0

\Delta G^o =-nFE^o_{ cell }......(1)

But

\Delta G^o =-RT ln K......(2)

From (1) and (2)

\Delta G^o =-RT ln K=-nFE^o_{ cell }

ln K =\frac{nFE^o_{ cell } }{RT }

ln K =\frac{ 2 \times 96500 \times 0.477 }{8.314 \times \left ( 25+273.15 \right ) }

ln K =37.139

K =1.3468 \times 10^{16}

Hence, the value of the equilibrium constant is 1.35 \times 10^{16}

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A gas occupies a volume of 0.2 L at 176 mm Hg. What volume will the gas occupy at 760 mm Hg?
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Answer:

V_2=0.046L

Explanation:

Hello,

In this case, we apply the Boyle's law as an inversely proportional relationship allowing us to understand the pressure-volume behavior as shown below:

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Ronald has a candy mixture. It has brown chocolate pieces and various colored hard candy pieces. All the candy pieces are the sa
Keith_Richards [23]

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A and E for sure.

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Lactic acid builds up in muscle during exercise, and contributes to the feeling of sore muscles afterwards. In blood, a normal a
shtirl [24]

Answer:

The smaller number in pounds per gallon is 3.59 × 10⁻⁴ pounds/gallon

The larger number in pounds per gallon is 1.72 × 10⁻³ pounds/gallon

Explanation:

For the smaller number in the range in pounds per gallon (pounds/gallon),

The smaller number in the range is 4.3 mg per dL

First, we will convert 4.3 mg to pounds

(NOTE: 1 g = 0.00220462 pound)

Then, for 4.3 mg in pounds

4.3 mg = 4.3 × 10⁻³ g = 0.0043 g

Now, If 1 g = 0.00220462 pound

Then, 0.0043 g =

(0.0043 × 0.00220462) pound = 9.48 × 10⁻⁶ pound

Also, we will convert dL to gallon

(NOTE: 1L = 0.264172 gallon)

Then, 1 dL = 0.0264172 gallon

Hence, 4.3 mg per dL is 9.48 × 10⁻⁶ pound / 0.0264172 gallon

= 3.59 × 10⁻⁴ pounds/gallon

Hence, the smaller number in pounds/gallon is 3.59 × 10⁻⁴ pounds/gallon

Now, for the larger number in the range in pounds per gallon (pounds/gallon),

The larger number in the range is 20.6 mg per dL

First, convert 20.6 mg to pounds

20.6 mg = 20.6 × 10⁻³ g = 0.0206 g

If 1 g = 0.00220462 pound

Then, 0.0206 g =

(0.0206 × 0.00220462) pound = 4.54 × 10⁻⁵ pound

Recall that, 1 dL = 0.0264172 gallon

Then, 20.6 mg per dL is 4.54 × 10⁻⁵ pound / 0.0264172 gallon

= 1.72 × 10⁻³ pounds/gallon

Hence, the larger number in pounds per gallon is 1.72 × 10⁻³ pounds/gallon

5 0
3 years ago
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