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julia-pushkina [17]
3 years ago
6

Solve for x. a=1/2h(b x)

Mathematics
1 answer:
fredd [130]3 years ago
5 0
A = 1/2 h(b + x)
2a = h(b + x)
2a/h = b + x
x = 2a/h - b
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Serena has attached a 10 inch ribbon to the corners of a frame to hang it on the wall. The frame 9 inches wide. How far above th
kherson [118]

Answer: The hook would be 2.2 inches (approximately) above the top of the frame

Step-by-step explanation: Please refer to the picture attached for further details.

The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (longest side) and AB and BC are the other two sides

5^2 = 4.5^2 + BC^2

25 = 20.25 + BC^2

Subtract 20.25 from both sides of the equation

4.75 = BC^2

Add the square root sign to both sides of the equation

2.1794 = BC

Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches

4 0
2 years ago
You have 1 pizza, and cut off all the crust from it so that the crust forms a line. How long is this line in terms of pizza leng
Mrrafil [7]

Answer:

as long as a pizza crust

Step-by-step explanation:

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5 0
2 years ago
Please answer this question now
Alexeev081 [22]

Answer:

Area = 400.4 m^2

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

\frac{u}{sin(U)} = \frac{w}{sin(W)}

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

\frac{29}{sin(33)} = \frac{w}{sin(34)}

Cross multiply

29*sin(34) = w*sin(33)

Divide both sides by sin(33) to make w the subject of formula

\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}

\frac{29*sin(34)}{sin(33)} = w

29.77 = w

UV = w = 30 m (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

area = \frac{1}{2}*u*w*sin(V)

= \frac{1}{2}*29*30*sin(113)

= \frac{29*30*sin(113)}{2}

Area = 400.4 m^2 (to nearest tenth).

4 0
3 years ago
What are the first 4 terms in the sequence represented by the expression 2n+3?
alekssr [168]

Answer:

cccccc

Step-by-step explanation:

hope this helps.

4 0
2 years ago
This system of equations has A. exactly one solution B. no solution C. infinitely many solution​
german

Answer:

C.

Step-by-step explanation:

This is because both lines are parallel, leaving infinite solutions.

5 0
3 years ago
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