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4 years ago

How to solve these 1. 8/2 * 6 2. 5/2 * 7 3. 7/2 * 1

Mathematics

2 answers:

andre [41]4 years ago

8 0

<h2>Answer:</h2><h3>Part 1.</h3>

Question 1. 8/2 * 6

Solution:

8/2 * 6 = 48/2 = 24

Answer of question 1 is 24.

Question 2. 5/2 * 7

Solution:

5/2 * 7 = 35/2 = 17.5

Answer of question 2 is 17.5.

Question 3. 7/2 * 1

Solution:

7/2 * 1 = 7/2 = 3.5

Answer of question 3 is 3.5.

Irina18 [472]4 years ago

5 0

1. 8/2 * 6

We multiply the numerator with the whole number and then simplify the fraction.

8 *6 = 48. then divide by 2 gives us 24

$\frac{8}{2} * 6= \frac{48}{2}=24$

2. 5/2 * 7

We multiply the numerator with the whole number and then simplify the fraction.

5 times 7 = 35

$\frac{5}{2} * 7= \frac{35}{2}$

3. 7/2 * 1

We multiply the numerator with the whole number and then simplify the fraction.

7 times 1 =7

$\frac{7}{2} * 1= \frac{7}{2}$

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This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying $c^2$ . This is the second line. Then, you could take the square of the $4c^2$ , ant try to create a factor () () that will correspond to the expression in the second line. That is, we want $4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)$

In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have $(2c + 6) (2c +7)$

The last step is divide by the number that we multipy in the first step.

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