Answer:
See below.
Step-by-step explanation:
I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.
♦ The midline's length is the average of the lengths of the top and bottom parallel sides.
Use this equation and substitute values given in each problem, then solve for the missing information.
1. AL = x, CE = 9, OR = 5
2. AL = <em>m</em> - 4, CE = 15, OR = 17
3. OR = y + 5, AL = 15, CE = 18
Answer:
around 904.78
Step-by-step explanation:
i got 904.78 but i cant read the answers properly so choose the closest one
Answer:
34.3 in, 36.3 in
Step-by-step explanation:
From the question given above, the following data were obtained:
Hypothenus = 50 in
1st leg (L₁) = L
2nd leg (L₂) = 2 + L
Thus, we can obtain the value of L by using the pythagoras theory as follow:
Hypo² = L₁² + L₂²
50² = L² + (2 + L)²
2500 = L² + 4 + 4L + L²
2500 = 2L² + 4L + 4
Rearrange
2L² + 4L + 4 – 2500 = 0
2L² + 4L – 2496 = 0
Coefficient of L² (a) = 2
Coefficient of L (n) = 4
Constant (c) = –2496
L = –b ± √(b² – 4ac) / 2a
L = –4 ± √(4² – 4 × 2 × –2496) / 2 × 2
L = –4 ± √(16 + 19968) / 4
L = –4 ± √(19984) / 4
L = –4 ± 141.36 / 4
L = –4 + 141.36 / 4 or –4 – 141.36 / 4
L = 137.36/ 4 or –145.36 / 4
L = 34.3 or –36.3
Since measurement can not be negative, the value of L is 34.3 in
Finally, we shall determine the lengths of the legs of the right triangle. This is illustrated below:
1st leg (L₁) = L
L = 34.4
1st leg (L₁) = 34.3 in
2nd leg (L₂) = 2 + L
L = 34.4
2nd leg (L₂) = 2 + 34.3
2nd leg (L₂) = 36.3 in
Therefore, the lengths of the legs of the right triangle are 34.3 in, 36.3 in
Answer:
4
Step-by-step explanation:
Answer:
Step-by-step explanation:
We will make a table and fill it in according to the information provided. What this question is asking us to find, in the end, is how long did it take the cars to travel the same distance. In other words, how long, t, til car 1's distance = car 2's distance. The table looks like this:
d = r * t
car1
car2
We can fill in the rates right away:
d = r * t
car1 40
car2 60
Now it tells us that car 2 leaves 3 hours after car 1, so logically that means that car 1 has been driving 3 hours longer than car 2:
d = r * t
car1 40 t + 3
car2 60 t
Because distance = rate * time, the distances fill in like this:
d = r * t
car1 40(t + 3) = 40 t+3
car2 60t = 60 t
Going back to the interpretation of the original question, I am looking to solve for t when the distance of car 1 = the distance of car 2. Therefore,
40(t+3) = 60t and
40t + 120 = 60t and
120 = 20t so
t = 6 hours.
