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kondor19780726 [428]
3 years ago
14

243.875 to nearest tenth, hundredth, ten, and hundred

Mathematics
1 answer:
spayn [35]3 years ago
4 0
The nearest tenth (243.9)
The nearest hundredth (243.88)
The nearest ten (240)
The nearest hundred (200)


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at 1:30 in the afternoon an old freight train and a new dart express train pull out of the new garland station going in opposite
zalisa [80]

Answer:

V_{E} = -22.5 / 15 = 1.5 miles/minute\\V_{F} = 7.5 / 15 = 0.5 miles/minute

Step-by-step explanation:

To answer this problem, we must bear in mind that the express train travels 3 times faster than the freight train.

If we call F the distance that the freight train travels and we call E at the distance that the express train travels, we must have the distance between them after 15 minutes it must be 30 miles.

So

F + E = 30\\

We also know that:

E = 3F

Since the express train travels 3 times faster than the freight train.

So, like both equations, we have to:

F + 3F = 30\\F = 30/4\\F = 7.5 miles\\

Then E = 7.5*3 = 22.5 miles in the opposite direction.

This is the distance you traveled in 15 minutes.

Therefore, the speed of the express train (V_{E}) is the distance traveled between the time it did

V_{E} = -22.5 / 15 = 1.5 miles/minute\\V_{F} = 7.5 / 15 = 0.5 miles/minute

3 0
3 years ago
A family has two cars. the first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of
Aliun [14]
Let x and y represent the numbers of gallons used by the 40 mpg and 35 mpg cars, respectively.
.. x +y = 40 . . . . . . . . . . .total consumption is 40 gallons
.. 40x +35y = 1525 . . . . total miles driven = 1525

Multiply the first equation by 40 and subtract the second.
.. 40(x +y) -(40x +35y) = 40(40) -(1525)
.. 5y = 75
.. y = 15
.. x = 40 -15 = 25

The 40 mpg car consumed 25 gallons.
The 35 mpg car consumed 15 gallons.
7 0
3 years ago
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
Mr. Carandang sold a total of 1,790 prints of one of his drawings. Out of all 1,273 unframed prints that he sold, 152 were small
vlada-n [284]

Answer: 517

Step-by-step explanation:

8 0
3 years ago
T/3 > Solve > 15. Graph the solution 3 The solution is​
MissTica

Answer:

T > 45

Step-by-step explanation:

Given

\frac{T}{3} > 15

Required

Graph the solution

\frac{T}{3} > 15

Multiply both sides by 3

3 * \frac{T}{3} > 15*3

T > 15*3

T > 45

<em>See attachment for graph (Assume T is on the x-axis)</em>

7 0
3 years ago
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