H2O (water) has 2 hydrogen atoms and 1 oxygen atom.
The way you want to find the percent composition would be by breaking down the problem like so:
K= atomic mass of K which is 39.098
Mn = atomic mass of Mn which is 54.938
O= atomic mass of o which is 15.999
Then you want to add 39.098+ 54.938+ 15.999 and you get 110.035 which is the molar mass for KMnO
Then you want to take each molar mass and then divide it 110.035 and multiply by 100
Ex. K = 39.098/ 110.035 and the multiply what you get by a 100
You do this for the other elements as well good luck!
Answer:
Antibacterial specifically refers to an inhibition of growth of bacteria, whereas antibiotics refer to a general inhibition of growth of microorganisms, which could include bacteria and viruses.
Answer:
Here's what I've found
Explanation:
Refer to the attachment !
Answer:
Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6
Bromocresol green, color change from pH = 4.0 to 5.6
Explanation:
The equation for the reaction is :
![C_2H_5NH_2_(_a_q_) + H^+_(_a_q_) --- C_2H_5NH_{3(aq)}^+](https://tex.z-dn.net/?f=C_2H_5NH_2_%28_a_q_%29%20%20%20%20%20%2B%20%20%20%20%20H%5E%2B_%28_a_q_%29%20%20%20---%20%20%20%20%20%20C_2H_5NH_%7B3%28aq%29%7D%5E%2B)
concentration of
= 10%
10 g of
in 100 ml solution
molar mass = 45.08 g/mol
number of moles = 10 / 45.08
= 0.222 mol
Molarity of ![C_2H_5NH_2(aq) = 0.222 \times \frac{1000}{100}mL](https://tex.z-dn.net/?f=C_2H_5NH_2%28aq%29%20%3D%200.222%20%5Ctimes%20%5Cfrac%7B1000%7D%7B100%7DmL)
= 2.22 M
number of moles of
in 20 mL can be determined as:
![= 20 mL \times 2.22 M= 44*10^{-3} mole](https://tex.z-dn.net/?f=%3D%2020%20mL%20%5Ctimes%20%202.22%20M%3D%2044%2A10%5E%7B-3%7D%20mole)
Concentration of ![C_2H_5NH_2(aq) = \frac{44*10^{-3}*1000}{20}](https://tex.z-dn.net/?f=C_2H_5NH_2%28aq%29%20%3D%20%5Cfrac%7B44%2A10%5E%7B-3%7D%2A1000%7D%7B20%7D)
= 2.22 M
Similarly, The pKa Value of
is given as 10.75
pKb value will be: 14 - pKa
= 14 - 10.75
= 3.25
the pH value at equivalence point is,
![pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]](https://tex.z-dn.net/?f=pH%3D%20%5Cfrac%7B1%7D%7B2%7DpKa%20-%20%5Cfrac%7B1%7D%7B2%7DpKb-%5Cfrac%7B1%7D%7B2%7Dlog%5BC%5D)
![pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]](https://tex.z-dn.net/?f=pH%20%3D%20%5Cfrac%7B14%7D%7B2%7D-%5Cfrac%7B3.25%7D%7B2%7D-%5Cfrac%7B1%7D%7B2%7Dlog%20%5B2.22%5D)
![pH = 5.21](https://tex.z-dn.net/?f=pH%20%3D%205.21)
Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6