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3 years ago

WILL MARK BRAINLIEST _________ are the outermost electrons of an atom

Chemistry

2 answers:

Minchanka [31]3 years ago

5 0

Valence shell :) is the outermost electrons of an atom

anastassius [24]3 years ago

3 0

Answer:

valence shell, and the electrons found in it are called valence electrons.

Explanation: i think hope this helps u

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Determine the poh of 0.01 molar solution of carbonic acid

Veronika [31]

Hello!

Data:

Molar Mass of H2CO3 (carbonic acid)

H = 2*1 = 2 amu

C = 1*12 = 12 amu

O = 3*16 = 48 amu

------------------------

Molar Mass of H2CO3 = 2 + 12 + 48 = 62 g/mol

Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:

M (molarity) = 0.01 M (Mol/L) → $1*10^{-2}\:M$

Use: Ka (ionization constant) = $4.4*10^{-7}$

$\alpha^2 (degree\:of\:ionization) = ?$

$Ka = M * \alpha^2$

$4.4*10^{-7} = 1*10^{-2}*\alpha^2$

$1*10^{-2}*\alpha^2 = 4.4*10^{-7}$

$\alpha^2 = \dfrac{4.4*10^{-7}}{1*10^{-2}}$

$\alpha^2 = 4.4*10^{-7-(-2)}$

$\alpha^2 = 4.4*10^{-7+2}$

$\alpha^2 = 4.4*10^{-5}$

$\alpha = \sqrt{4.4*10^{-5}}$

$\boxed{\alpha \approx 2.09*10^{-5}}$

Now, we will calculate the amount of Hydronium [H3O+] in carbonic acid (H2CO3), multiply the acid molarity by the degree of ionization, we will have:

$[ H_{3} O^+] = M* \alpha$

$[ H_{3} O^+] = 1*10^{-2}* 2.09*10^{-5}$

$[ H_{3} O^+] = 2.09*10^{-2-5}$

$\boxed{[ H_{3} O^+] = 2.09*10^{-7}}$

And finally, we will use the data found and put in the logarithmic equation of the PH, thus:

Data:

$pH = \:?$

$[ H_{3} O^+] = 2.09*10^{-7}$

apply the data to formula

$pH = - log[H_{3} O^+]$

$pH = - log[2.09*10^{-7}]$

$pH = 7 - log\:2.09$

$pH = 7 - 0.32$

$\boxed{pH = 6.68}$

Note:. The pH <7, then we have an acidic solution (weak acid).

Now, let's find pOH by the following formula:

$pH + pOH = 14$

$6.68 + pOH = 14$

$pOH = 14 - 6.68$

$\boxed{\boxed{pOH = 7.32}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

3 0

3 years ago

PLEASE ANSWER

stepladder [879]

Answer:

C. Light slows down as it goes through more dense materials.

8 0

3 years ago

a compound of general formula qr contains no hydrogen, q is the alkali metal of lowest atomic mass, and r contains the elements

nikklg [1K]

Answer:

Li2CO3 - Lithium carbonate

Explanation:

If you look at the periodic table of elements, you will see that, from all alkali metals, Lithium is the one with the lowest atomic mass. So we can conclude that the element q in the compound qr is Lithium.

The task says that in the compound qr, r contains the elements oxygen and carbon in a 3:1 ratio. It means that we have 3 oxygen and 1 carbon atom in this compound, which can be written as CO3.

From the information above, we can conclude the compound that we are looking for is Li2CO3 - Lithium carbonate.

4 0

4 years ago

Sodium bromide+ Lithium Based on Single replacement

Helga [31]

Answer:

the answer will be lithium bromide + sodium

Explanation:

because displace sodium from bromine there by liberating sodium as an element in the product side

6 0

3 years ago

4 Na + O2 → 2 Na2O 6.79 moles of O2 will react to form how many moles of Na2O?

Nataly_w [17]

Answer:

13.94moles of Na₂O

Explanation:

The balanced reaction expression is given as:

4Na + O₂ → 2Na₂O

Given parameters:

Number of moles of O₂ = 6.97moles

Unknown:

Number of moles of Na₂O

Solution:

To solve this problem;

1 mole of O₂ will produce 2 moles of Na₂O ;

6.97 moles of O₂ will produce 6.97 x 2 = 13.94moles of Na₂O

6 0

3 years ago