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soldi70 [24.7K]

3 years ago

13

What is the answer to this

1 answer:

Kamila [148]3 years ago

8 0

205 units. If those are millimeters then it would be 205 millimeters. If its supposed to be in meters, it would be 0.205 meters.

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Please help due today

Murljashka [212]

The answer for the question is c.

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3 years ago

Exposure to what type of radiant energy is sensed by human skin as warmth?

larisa86 [58]

The answer is C.gamma rays

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3 years ago

Read 2 more answers

Pls help me with this atomic number worksheet I will make you the brainiest worth 25 points

ELEN [110]

Answer:

HELLO THERE!

I HOPE MY ANSWER WILL HELP YOU :)

Explanation:

PLEASE NOTE; I HAVE WRITTEN THE ATOMIC NUMBER IN BRACKETS, NEXT TO THE SYMBOL OF THE ELEMENT

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3 years ago

A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to

Drupady [299]

Answer : The final temperature of the mixture is $29.6^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of iron = $0.499J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of iron = 39.9 g

$m_2$ = mass of water = $Density\times Volume=1g/mL\times 50.0mL=50.0g$

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of iron = $78.1^oC$

$T_2$ = initial temperature of water = $25.0^oC$

Now put all the given values in the above formula, we get

$(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC$

$T_f=29.6^oC$

Therefore, the final temperature of the mixture is $29.6^oC$

8 0

3 years ago

An atom has 6 electrons in its outer orbit. It will most likely form an ion with a charge of:

GenaCL600 [577]

Answer:

c

Explanation:

4 0

3 years ago