Answer:
1. 276 g of NO₂
2. 34.8 moles of LiO
3. 4.23×10²⁵ molecules of SO₂
4. 540 g of H₂O
5. 224 g CO
Explanation:
Let's define the molar mass of the compound to define the moles or the grans of each.
Molar mass . moles = Mass
Mass (g) / Molar mass = Moles
1. 6 mol . 46 g / 1 mol = 276 g of NO₂
2. 800 g . 1mol / 22.94 g = 34.8 moles of LiO
3. To determine the number of molecules, we convert the mass to moles and then, we use the NA (1 mol contains 6.02×10²³ molecules)
4500 g . 1mol / 64.06 g = 70.2 moles of SO₂
70.2 mol . 6.02×10²³ molecules / 1 mol = 4.23×10²⁵ molecules of SO₂
4. 30 mol . 18g / 1 mol = 540 g of H₂O
5. 8 mol . 28g / 1mol = 224 g CO
Answer: A=1
Explanation:
First, distribute the 3: 3x3A, 3x-5, the equation is now 2A+9A-15= -4
Now add the 2A plus 9A, the equation is now 11A-15= -4
Solve algebraically:
11A-15= -4
+15 +15 11A=11 Divide by 11 on each side
A=1
A. loses electron, bc electrons are negatively charged, protons are positively charged, when electrons are lost, that means there are more protons more
Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
