Answer:
A = -14.87 i ^ + 8.42 j ^ + 0 k ^
B = -25.41 i ^ -12.0 j ^ + 0 k ^
Explanation:
For this exercise let's use trigonometry by decomposing to vectors
vector A
module 17.1 with an angle of 150.5 counterclockwise.
Sin 150.5 = / A
cos 150.5 = Ax / A
A_{y} = A sin 150.5 = 17.1 sin 150.5
Aₓ = A cos 1505 = 172 cos 150.5
A_{y} = 8,420
Aₓ = -14.870
the vector is
A = -14.87 i ^ + 8.42 j ^ + 0 k ^
Vector B
= 28.1 sin 205.3
Bₓ = 28.1 cos 205.3
B_{y} = -12.009
Bₓ = -25.405
the vector is
B = -25.41 i ^ -12.0 j ^ + 0 k ^
Answer:
the difference in the amount of energy that charge carriers have between two points in a circuit
Explanation:
Answer:
11.82 N upward and parallel to the incline.
Explanation:
Let g = 9.81 m/s2. Gravity that acts on the bin has a magnitude of
W = mg = 3*9.81 = 29.43 N
The gravity component that is parallel to the 40 degree incline is
If the bin is moving at constant speed, then the net force (parallel to the incline) is also 0. Gravity is balanced with the push force of 26 N and the friction force.
The magnitude of friction force is 26 - 18.9 = 7.08 N
The the bin is moving down the incline, then gravity is 18.9N , friction is 7.08 N, one must create an upward force of 18.9 - 7.08 = 11.82 N parallel with the incline to balance this.