<span>this may help you
As far as the field goes, the two charges opposite each other cancel!
So E = kQ / d² = k * Q / (d/√2)² = 2*k*Q / d² ◄
and since k = 8.99e9N·m²/C²,
E = 1.789e10N·m²/C² * Q / d² </span>
Explanation:
i wish I could help you but its not clear...
Answer:A is the correct ans...
Explanation:
part a)
Vector a has magnitude 12.3 and its direction is west, while Vector b has unknown magnitude and its direction is north. This means that the two vectors form a right-angle triangle, so a and b are two sides, while a+b is the hypothenuse.
We know the magnitude of a+b, which is 14.5, so we can use the Pythagorean theorem to calculate the magnitude of b:
![|b|=\sqrt{(a+b)^2-a^2}=\sqrt{(14.5)^2-(12.3)^2}=7.68](https://tex.z-dn.net/?f=%20%7Cb%7C%3D%5Csqrt%7B%28a%2Bb%29%5E2-a%5E2%7D%3D%5Csqrt%7B%2814.5%29%5E2-%2812.3%29%5E2%7D%3D7.68%20)
part b) The direction of the vector a+b relative to west can be found by calculating the tangent of the angle of the right-angle triangle described in the previous part; the tangent of the angle is equal to the ratio between the opposite side (b) and the adjacent side (a):
![tan x=\frac{b}{a}=\frac{7.68}{12.3}=0.62](https://tex.z-dn.net/?f=%20tan%20x%3D%5Cfrac%7Bb%7D%7Ba%7D%3D%5Cfrac%7B7.68%7D%7B12.3%7D%3D0.62%20)
And the angle is
![x=tan^{-1} (0.62)=31.8^{\circ}](https://tex.z-dn.net/?f=%20x%3Dtan%5E%7B-1%7D%20%280.62%29%3D31.8%5E%7B%5Ccirc%7D%20)
with direction north-west.
part c)
This is exactly the same problem as the one we solved in part a): the only difference here is that the hypothenuse of the triangle is now given by a-b rather than a+b. In order to find a-b, we have to reverse the direction of b, which now points south. However, the calculations to get the magnitude of b are exactly the same as before, since the magnitude of (a-b) is the same as (a+b) (14.5 units), therefore the magnitude of b is still 7.68 units.
part d)
Again, this part is equivalent to part b); the only difference is that b points now south instead of north, so the vector (a-b) has direction south-west instead of north-west as before. Since the magnitude of the vectors involved are the same as part b), we still get the same angle,
, but this time the direction is south-west instead of north-west.
Answer:
4
Explanation:
there are 4 complete wavelengths