Answer:
= 591.45 T/s
Explanation:
i = induced current in the loop = 0.367 A
R = Resistance of the loop = 117 Ω
E = Induced voltage
Induced voltage is given as
E = i R
E = (0.367) (117)
E = 42.939 volts
= rate of change of magnetic field
A = area of loop = 7.26 x 10⁻² m²
Induced emf is given as
= 591.45 T/s
Answer:
Energy is applied on the charge to do work.
Explanation:
Work is only be done when one charge moves against the electric field of anther charge that require huge amount of energy because both have same charge and the force of repulsion occurs between them. Work is defined as the product of force and displacement so from this equation we can conclude that work is done when a force is applied on an object and it moves in the direction in which force is applied. If the force or energy is removed from the charge which is present in the electric field of another charge so it moves away from that charge and the work is also be done..
Answer:
7.89x10¹°
Explanation:
10 to the power of 10
Sorry i dont understand how to type it
Answer:
The current flowing through the wire is 9 A.
Explanation:
Given;
quantity of charge passing through the wire, Q = 36 C
duration of the charge flow, t = 4 s
The current flowing through the wire is calculated as;
Q = It
I = Q / t
where;
I is the current flowing in the wire
I = 36/4
I = 9 A
Therefore, the current flowing through the wire is 9 A.
1. First answer
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3. Rotation
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