Answer:
108/5
Step-by-step explanation:
There is no information here, could you add more. There are no lines for us to help you with so this makes it confusing for others, add more information for us to be able to help.
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
(srt(3)/2, -1/2)
Step-by-step explanation:
x = rcos theta
r = 1 on unit circle
x = 1 cos (-pi/6)
x = sqrt(3)/2
y = r sin theta
y =1 sin (-pi/6)=
y = -1/2
