Find the indicated side of the triangle
2 answers:
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The solutions for the inequality are -
- (3, 3)
- (7, 7)
- (10, 10)
The general equation of a straight line is -
[y] = [m]x + [c]
where -
[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].
[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.
A inequality is used to compare two or more expressions. The straight line inequalities are of the form -
y > mx + c
y < mx + c
y ≥ mx + c
y ≤ mx + c
We have the following inequality -
x + 3y > 6
We can write -
x + 3y > 6
3y > - x + 6
y > (-1/3)x + 2
Refer to the graph of the inequality attached. The plotted points in the shaded region represent the solutions for the inequality. We can write -
- (3, 3)
- (7, 7)
- (10, 10)
Therefore, the solutions for the inequality are -
- (3, 3)
- (7, 7)
- (10, 10)
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