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3 years ago

Find the indicated side of the triangle

Mathematics

2 answers:

Svetlanka [38]3 years ago

6 0

Answer:

X=14

Step-by-step explanation:

Sin30=7/x

1/2=7/x

Cross multiply

2×7=14

1×x=x

X=14

Oksanka [162]3 years ago

3 0

7square root of 3 there’s no symbol

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A² + 6 from 7 plzz answer i gave u half of my points plz

omeli [17]

Answer:

a = 1

Step-by-step explanation:

First, you subtract 6 from both sides and you end up with a² = 1. Since one cannot be squared or square rooted, a = 1. I hope this helps!

7 0

3 years ago

Find the quotient. 36s^3t-26st ----------------- -2st Enter the correct answer.

MrRa [10]

Answer:

it is makeing me do it

Step-by-step explanation:

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3 years ago

Complete the identity. 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Need help!

chubhunter [2.5K]

The correct equation is P(t) = Po*e^(kt). Please enclose "kt" inside parentheses and use the " ^ " symbol to indicate exponentiation.

"k" is the growth constant, which here is 0.017. "t" is the number of yeasrs. P(7) is the population after 7 years. Po is the initial population, which in this case is 91 million.

The initial value, when t = 0, is 91 million.

After 7 years, the population, P(7), was P(7) = (91 million)*e^(0.017*7). This evaluates to P(7) = (91 million)*(1.070) = 96 million

8 0

3 years ago

A system of equations is given below. y=1/2x-3 and -1/2x-3. Which of the following statements best describes the two lines?

pantera1 [17]

"They have different slopes but the same y-intercept, so they have one solution" is the statement which best describes the two lines.

Answer: Option D

Step-by-step explanation:

Given equations:

$y=\left(\frac{1}{2} \times x\right)-3$

$y=\left(-\frac{1}{2} \times x\right)-3$

As we know that the slope intercept form of a line is

y = m x + c

So, from equation 1 and equation 2 we can see that

$m_{1}=\frac{1}{2} \quad \text { and } c_{1}=-3$

$m_{2}=-\frac{1}{2} \text { and } c_{2}=-3$

So, from the above expressions, we can say that both lines have different slopes but have same y – intercept with one common solution when x = 0.

4 0

3 years ago

Read 2 more answers

Find the indicated side of the triangle ​

Find the indicated side of the triangle