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anygoal [31]
3 years ago
14

The water level in an ocean bay changes at an average rate of 3 meters per hour. At this rate,how many hours would it take for t

he water level to change 12 meters?
Mathematics
2 answers:
Charra [1.4K]3 years ago
3 0

In this big ol' word problem, this is just an instance of basic multiplication/division.

If it takes it 1 hour for 3 meters...

12 ÷ 3 = 4.

It would take 4 hours for the water level to change to 12 meters.

Tanzania [10]3 years ago
3 0
Hi, the answer would be 4. 
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barxatty [35]

Answer:

-7

Step-by-step explanation:

Refer to the photo.

the slope=(0-g)/(5-4)

i.e. 7=(-g)/1

g=-7

3 0
3 years ago
A package of 4 pairs of insulated gloves costs ​$33.16. What is the unit price of the pairs of gloves​?
juin [17]

Answer:

$8.29

Step-by-step explanation:

Divide 4 by 33.16.

5 0
3 years ago
A bag of 12 ounces of popcorn costs $4.80. What is the unit rate? (in others words what is the cost for one ounce) *​
masha68 [24]

Answer:

0.4

Step-by-step explanation:

$4.80 divided by 12 = 0.4

5 0
3 years ago
Read 2 more answers
You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
Choose the model that represents the function
kirill [66]

Answer:

OPTION D

Step-by-step explanation:

We have to determine which option determines the function given above.

To determine the function, just substitute the values and compare LHS and RHS.

we have $ f(4) = 18 $

$ f(-2) = -12 $

$ f(0) = -2 $

$ f(-3) = -17 $

Here, $ x $ is the domain and $ f(x) $ is the co-doamin.

Therefore, $ x = \{4, -2, 0, -3\} $

Now, OPTION A: $ f(x) =  2x - 5 $

Substitute x = 4. We get f(x) = 3 $ \ne $ 18.

So, OPTION A is rejected.

Similarly, OPTION B: $ f(x) = 5x + 2 $

Substitute x = 4. We get f(4) = 22 $ \ne $18.

It is rejected as well.

Now, for OPTION C: $ f(x) = \frac{x}{2} - 5 $

Substitute x = 4. We get f(4) = -3 $ \ne $ 18.

So, OPTION C is also rejected.

OPTION D: $ f(x) =  5x - 2 $

Substitute x = 4. We get f(4) = 18.

Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.

8 0
3 years ago
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