So the way to calculate the slope from a line on a grid, we know that:

If we take the line RC, we count that the number of units that it rises is 3 units. However, it does not go to the right or to the left, therefore, it does not 'run' at all. It will be 0. So when we put this into a fraction:

we see that this answer comes out undefined. This is because there is a 0 in the denominator - so the slope for RC is undefined.
When we look at the line SC, we see that the units that it rises is -1 units (essentially it went down 1 unit), and we see that the number of units it 'ran' is 5 units. So let's put that into a fraction:

and we see that the slope for SC is

.
Answer:
The distance at which the timekeeper is the race car at the start is 50 feet.
Step-by-step explanation:
You know that the car's distance from the timekeeper is represented by
y=293*x +50
where x is time in seconds and y is distance in feet from the timekeeper's position.
You want to determine how far the timekeeper is from the race car at the start. That is, the distance the timekeeper is from the car when the time is equal to zero. This indicates that x = 0. Replacing x by that value in the expression of the distance of the car from the timekeeper as a function of time and solving:
y=293*0 +50
you get:
y=50
<u><em>The distance at which the timekeeper is the race car at the start is 50 feet.</em></u>
Answer:
5²
Step-by-step explanation:
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Answer:
d=√73=8.544
Step-by-step explanation:
Find distance (d) between market (0,8) , court house(6,5) and library(6,-1)
d between two pint is :
d=√(x2-x1)²-(y2-y1)²
d between market and court house:
d=√(6-0)²+(5-8)²
d=√36+9=√45 = 6.7082 ≅6.71 rounded to the nearest hundredths
d between courthouse and the library:
d=√(6-6)²+(-1-5)²
d=√36=6
the distance that Runner A ran=6.71+6=12.71
the distance from the library to the school:
d=√(6-(-2))²+(-1-(-4))²
d=√8²+3²
d=√64+9
d=√73=8.544 ( rounded to the nearest hundredth)
Runner B went 8.544 further than Runner A before stopping at school ( which is the distance between the library and the school.