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Ira Lisetskai [31]
3 years ago
7

Can I get some help on this please? This is part 1 I will post part 2 later.

Mathematics
1 answer:
Darya [45]3 years ago
3 0

Answer:

-2/3 (fixed it)

Step-by-step explanation:

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Read 2 more answers
Given: △ABC; AB=BC, m∠BDA = 60°, BD=4 cm, BD ⊥ BA . Find: DC, AC.
vekshin1

Answer:

DC = 10.93 cm ,  AC = 9.8 cm

Step-by-step explanation:

From trigonometry;

⇒ Tan 60 = AB/BD

⇒AB = BD Tan 60 ( where BD = 4 cm )

⇒ AB = 6.93 cm

Also, AB=BC , therefore;

⇒ BC = 6.93 cm

⇒ Cos 60 = BD/AD

⇒ AD = BD/ Cos 60 = 4/Cos 60

⇒ AD = 8 cm

From Pythagoras theorem;

⇒ AC^{2} = AB^{2} + BC^{2} = (6.93)^{2} + (6.93)^{2}

⇒ AC = \sqrt{96.05} = 9.80 cm

⇒ DC = BD + BC = 4 + 6.93

⇒ DC = 10.93 cm

8 0
3 years ago
The midpoint of AB is M(3, -1). If the coordinates of A are (5,1), what are the
Vera_Pavlovna [14]

Given parameters:

Midpoint of AB =  M(3, -1)

Coordinates of A = (5,1)

Unknown:

Coordinates of B = ?

Solution:

To find the mid point of any line, we use the expression below;

              x_{m}   = \frac{x_{1} + x_{2}  }{2}    and y_{m}  = \frac{y_{1} + y_{2}  }{2}

where x_{m}  and y_{m} = coordinates of the mid points = 3 and -1

   x₁  = 5 and y₁ = 1

  x₂ = ?  and y₂ = ?

Now let us input the variables and solve,

            3  = \frac{5 + x_{2} }{2}           and     -1 = \frac{1 + y_{2} }{2}

    5 +  x₂  = 6                          -2 = 1  + y₂

            x₂ = 1                             y₂ = -2 -1 = -3

The coordinates of B = 1, -3

6 0
3 years ago
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