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liubo4ka [24]
3 years ago
14

Please help! Correct answer only, please!

Mathematics
1 answer:
sukhopar [10]3 years ago
4 0

Answer: A. \left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

Step-by-step explanation:

The question is asking us to find the product of the matrices. The key difference is the second A has a little <em>T</em> in the exponent. This <em>T</em> means transpose. You multiply A by the transpose of A. To find the transpose, you turn the rows into columns.

A^T=\left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right]

Now that we have our transpose, we can multiply the matrices.

\left[\begin{array}{ccc}5&2\\3&-1\\\end{array}\right] \left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right] =\left[\begin{array}{ccc}5*5+2*2&5*3+2(-1)\\3*5+2(-1)&3*3+(-1)(-1)\\\end{array}\right] =\left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

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see the attached figure to better understand the problem  

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A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.  

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m∠E = m∠Y  

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