Answer: (1,-1)
Step-by-step explanation:
Midpoint of BC=(6+4)/2, (3–1)/2. =(5,1)
Slope of BC is (3+1)/4–6)= 4/-2 = -2
Slope of perpendicular bisector of BC =+1/2
Eqn of perpendicular bisector is : Y-1 =1/2 (x-5)
Y=1/2 •(x-5) +1
Midpoint of AB. (6–2)/2, (3–1)/2 ={2,1)
Slope of AB is(3+1)/(-2–6) = 4/-8 =-1/2
Slope of perpendicular bisector = +2
Eqn of perpendicular bisector is Y-1. =2( X-2)
Y=2X-4+1 = 2X -3
Solving Y=(X-5)/2 +1
& Y=2X-3
2X-3 =(x-5/2)+1
2X-4 =(x-5/2)
4X-8 = x-5
3X =3
X=1
Y= 2×1–3= -1
Circumcentre is(1,-1)
Answer:
$192
Step-by-step explanation:
→ Set up equation
3.40h + 0.20u
→ Substitute in the numbers
( 3.40 × 40 ) + ( 0.20 × 280 )
→ Simplify
192
Answer:
12xy - x^4y - 2y^3
It seems difficult up close, but it's fairly simple. You need to write the same varibles out, group and combine like terms, and you should get this answer.
Answer:
-7
Step-by-step explanation:
substitute both x's for 7:
(-8(7)+4)+ (3(7)2+5)
= -54 + 47
= -7
Answer:
64
Step-by-step explanation:
4^3=64
4*4=16
16*4=64