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4 years ago

Find the diameter of a circle whose equation is x2+(y−2)2=100x2+(y−2)2=100.

1 answer:

3 0

Find the diameter of a circle whose equation is x2+(y−2)2=100x2+(y−2)2=100.

400

20

100

10
 i would say the answer is 10

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The diameter of a circle is 9 centimeters. Find the area to the nearest tenth.

Umnica [9.8K]

Answer:

63.6 square cm

Step-by-step explanation:

$d = 9 \: cm \implies \: r = 4.5 \: cm \\ area \: of \: circle \\ = \pi {r}^{2} \\ = 3.14 \times ( {4.5})^{2} \\ = 3.14 \times 20.25 \\ = 63.585 \\ = 63.6 \: {cm}^{2} \\$

8 0

3 years ago

Find the missing Side lengths.

adelina 88 [10]

{ Answer(s) }

Left side of big triangle (X & Y) : 15

Bottom side of big triangle (Y & Z) : 20

{ Explanation }

We know the top sides of both triangles. To find out how many units they are separated by, we need to divide 5 by 25.

25 / 5 = 5

Now we can continue.

3 * 5 = 15

4 * 5 = 20

The missing sides are 15 and 20.

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7 0

4 years ago

Scott and his family want to hike a trail that is 1,365 miles long. They will hike equal parts of the trail on 12 different hiki

podryga [215]

Answer:

113.75

Step-by-step explanation:

all you have to do is divide 1,365 by 12 to get the answer which is^^

4 0

3 years ago

Probability The average time between incoming calls at a switchboard is 3 minutes.if a call has just come in,the probability tha

Stels [109]

Answer:

a) 0.1535

b) 0.4866

c) 0.8111

Step-by-step explanation:

The probability that the next call come within the next t minutes is:

$p(t) = 1 -e ^{- t/3}$

According to this model,

a) the probability that a call in comes within 1/2 minutes is $p(t) = 1 -e ^{- (1/2)/3}$ =0.1535

b) the probability that a call in comes within 2 minutes is $p(t) = 1 -e ^{-2/3}$ =0.4866

c) the probability that a call in comes within 5 minutes is $p(t) = 1 -e ^{-5/3}$ =0.8111

6 0

3 years ago

If x>7, then |x|>7. |y|>7, so y=7 Valid or invalid?

Alex

$\text{if }x>7\text{, then }|x|>7$ is a valid argument

$|y|>7\text{, so }y=7$ is not a valid argument

For the first argument: $\text{if }x>7\text{, then }|x|>7$

From the definition of absolute value function

$|x|=x$ if $x\ge0$

That is every positive number is its own absolute value. Since

$x>7\implies x\ge0$ ,

we can argue that

$x>7\implies |x|>7$

so the first argument is valid

For the second argument: $|y|>7\text{, so }y=7$

From the definition of absolute value function

$|y|:=\left \{ {y\text{ if }y\ge0}\atop{-y\text{ if }y$

This means that

$|y|>7:=\left \{ {y>7\text{ if }y\ge0}\atop{-y>7\text{ if }y$

$|y|>7:=\left \{ {y>7\text{ if }y\ge0}\atop{y$

no part of the definition allow for the option $y=7$ . So the second argument is not valid.

Learn more here: brainly.com/question/11897796

7 0

3 years ago