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2 years ago

Card Name (APR %) Existing Balance Credit Limit

Mathematics

1 answer:

torisob [31]2 years ago

3 0

Step-by-step explanation:

Dunno. wish there were more points than this though. bye

if his wasn't algebra, I would've answered answered. hope you have your answer by now though.

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At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes

lakkis [162]

Answer:

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

Step(i):-

Mean of the Population = 1900

Given random sample size 'n' = 45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

Null Hypothesis:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

Alternative Hypothesis :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step(ii):-

Test statistic

$t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }$

t = -900 /33.54 = -26.517

|t| = |-26.517|=26.517

Degrees of freedom

γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0

2 years ago

In 2 yrs time ella will be twice the age she was 5 yrs ago. how old is she now?

chubhunter [2.5K]

8 because 2 times 5 is ten

7 0

2 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

) Using the chart, approximate the limit of the function f(x) = sin x/ x as x approaches zero. Note the numbers are in radians:

Rashid [163]

Answer:

Step-by-step explanation:

We are given that

$f(x)=\frac{sinx}{x}$

Numbers are in radians

Substitute x=-1

$f(-1)=\frac{sin(-1)}{-1}=0.84$

Substitute x=-0.25

$f(-0.25)=\frac{Sin(-0.25)}{-0.25}=0.989$

Substitute x=-0.01

$f(-0.01)=\frac{sin(-0.01)}{-0.01}=0.999$

Substitute x=-0.005

$f(-0.005)=\frac{sin(-0.005)}{-0.005}=0.999$

Substitute x=0.005

$f(0.005)=\frac{sin(0.005)}{0.005}=0.999$

Substitute x=0.01

$f(0.01)=\frac{sin(0.01)}{0.01}=0.999$

Substitute x=0.25

$f(0.25)=\frac{sin(0.25)}{0.25}=0.989$

Substitute x=1

$f(1)=\frac{sin(1)}{1}=0.84$

Therefore, $\lim_{x\rightarrow 0}\frac{sinx}{x}=1$

8 0

3 years ago

A survey found that women's heights are normally distributed with mean 63.7 . And standard deviation 3.7 . The survey also foun

san4es73 [151]

Complete question :

A survey found that women's heights are normally distributed with mean 63.6 in and standard deviation 3.7 in. The survey also found that men's heights are normally distributed with mean 69.3 in and standard deviation 3.7 in. Consider an executive jet that seats six with a doorway height of 55.7 in.

1-What percentage of adult men can fit through the door without bending?

2-) Does the door design with a height of 56.35in. appear to be adequate? Why didn't the engineers design a larger door? Choose answer below

A. The door design is inadequate, because every person needs to be able to get into the aircraft without bending. There is no reason why this should not be implemented.

B. The door design is adequate, because the majority of people will be able to fit without bending. Thus, a larger door is not needed.

C. The door design is inadequate, but because the jet is relatively small and seats only six people, a much higher door would require major changes in the design and cost of the jet, making a larger height not practical.

D. The door design is adequate, because although many men will not be able to fit without bending, most women will be able to fit without bending. Thus, a larger door is not needed.

Answer:

A.) 0.135%

B.) C. The door design is inadequate, but because the jet is relatively small and seats only six people, a much higher door would require major changes in the design and cost of the jet, making a larger height not practical.

C.)

Step-by-step explanation:

Percentage of adult men that can fit the door without bending :

Obtain the Zscore :

Mean height of men, m = 67.5

Standard deviation, s = 3.7

Zscore = (x - m) / s ; where x = 56.4

Zscore = (56.4 - 67.5) / 3.7

Zscore = - 11.1 / 3.7

Zscore = - 3

P(Z < - 3) = 0.0013499 (Z probability calculator)

P(Z < - 3) = 0.0013499 * 100% = 0.13499%

8 0

3 years ago