Question

Solid lead(ii) sulfide reacts with aqueous hydrochloric acid to form solid lead(ii) chloride and dihydrogen sulfide gas. express your answer as a chemical equation. identify all of the phases in your answer.

Answer 1

PbS(s) + 2HCl(aq) → PbCl₂(s) + H₂S(g)

PbS(s) + 2H⁺(aq) + 2Cl⁻(aq) → PbCl₂(s) + H₂S(g)

PbS + 2H⁺ → Pb²⁺ + H₂S
Pb²⁺ + 2Cl⁻ → PbCl₂

Answer 2

Answer: The chemical equation is;

$PbS(s)+2HCl(aq)\rightarrow PbCl_2(s)+H_2S(g)$

Explanation:

The described reaction between solid lead sulfide and aqueous hydrochloric acid can represented in the in the form of chemical equation as given below:

$PbS(s)+2HCl(aq)\rightarrow PbCl_2(s)+H_2S(g)$

1 mol of lead(ii) sulfide reacts with hydrochloric acid to give 1 mole of lead chloride and hydrogen sulfide gas.