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Slav-nsk [51]
3 years ago
9

Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o

smotic pressures required for this process can be as high as 19.6 atm. What would the molar concentration of the tree sap have to be to achieve this pressure on a day when the temperature is 32°C ?
Chemistry
1 answer:
liberstina [14]3 years ago
4 0

Answer: Molar concentration of the tree sap have to be 0.783 M

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iCRT

where,

\pi = osmotic pressure of the solution = 19.6 atm

i = Van't hoff factor = 1 (for non-electrolytes)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 32^oC=[273+32]=305K

Putting values in above equation, we get:

19.6atm=1\times C\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 305K

C=0.783M

Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C

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marta [7]

<u>Answer:</u> The mass of carbon in given amount of carvone is 47.52 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of carvone = 55.4 g

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Putting values in equation 1, we get:

\text{Moles of carvone}=\frac{55.4g}{150.22g/mol}=0.369mol

The chemical formula of carvone is C_{10}H_{14}O

This contains 10 moles of carbon atom, 14 moles of hydrogen atom and 1 mole  of oxygen atom

Now, calculating the mass of carbon in carvone from equation 1, we get:

Molar mass of carbon = 12 g/mol

Moles of carbon = (10 × 0.396) = 3.96 moles

Putting values in equation 1, we get:

3.96mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=(3.96mol\times 12g/mol)=47.52g

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3 years ago
Position vs Time
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= 25 ppm

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