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Slav-nsk [51]
3 years ago
9

Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o

smotic pressures required for this process can be as high as 19.6 atm. What would the molar concentration of the tree sap have to be to achieve this pressure on a day when the temperature is 32°C ?
Chemistry
1 answer:
liberstina [14]3 years ago
4 0

Answer: Molar concentration of the tree sap have to be 0.783 M

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iCRT

where,

\pi = osmotic pressure of the solution = 19.6 atm

i = Van't hoff factor = 1 (for non-electrolytes)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 32^oC=[273+32]=305K

Putting values in above equation, we get:

19.6atm=1\times C\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 305K

C=0.783M

Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C

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Commercial concentrated aqueous ammonia is 28% NH3 by mass and has a density of 0.90 g/mL. You may want to reference (Pages 539
katen-ka-za [31]

Answer:

The molarity of this solution is 14.82 mol/dm3 or 14.82 mol/L

Explanation:

  • Molarity is the number of mole present in 1 Litre of solution. Molarity of a solution is a term referred to as concentration of a solution. The unit of Molarity is Mol/dm3 or Mol/L.
  • let us make an assumption that the volume of the ammonia solution is 1L or 1dm3. Also, 1L = 1000 mL.

Step 1: calculate the mass of the solution

Density = 0.90g/ml (from the question)

             Density = mass/ volume

Therefore Mass = density x  volume

                          =  0.90g/ml x 1000ml

                mass =  900 g

Step 2: calculate the mass of NH3 present in the solution

Since the concentrated aqueous of ammonia is 28%, It signifies that 1000ml of the solution contains 28% Ammonia

Recall from the above calculation that the mass of 1000 ml of solution is 900 g.

Therefore the mass of ammonia will be 28% of 900 g

                  mass of NH3 = 0.28 x 900 g

                                         = 252 g

Step 3: calculate the number of mole of NH3

        mole = mass/ molar mass

molar mass of NH3 = 17 g/mol

Therefore mole of NH3 = 252/17

                                       = 14.82 mol

Step 4: Calculate Molarity

            Molarity = number of moles/ volume of solution in Litre (L)

            Molarity = 14.82 / 1

            Molarity = 14.82 mol/L

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