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photoshop1234 [79]
3 years ago
5

What needed to be present in marine mud to form fossil fuels?

Chemistry
1 answer:
UkoKoshka [18]3 years ago
8 0
When organisms and plants died and sank to the bottom of swamps and oceans, brown soil-like materials called peat are formed. Over millions of years, the peat became covered with sand, clay and other minerals and the peat is converted into layers of sedimentary rocks. After a long time, different type of fossil fuels are formed.
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What is the oxidation number of nitrogen in the nitrate ion NO31−?
ahrayia [7]

In No3-1 the oxidation number of oxygen is -5 so oxidation number of N would be +5

8 0
3 years ago
Read 2 more answers
Zn + 2HCl ---> ZnCl2 + H2 1. Is the equation above balanced or unbalanced? How do you know? (Hint: How many atoms of each typ
Arisa [49]

Answer:Balance. Acid+metal->salt+hydrogen.1 molecule od zinc contains 1 zinc atom.2 molecule of HCl contains 2 atoms hydrogen and 2 chlorine.1 molecule of Zncl2 contain one atom of zinc and two atom of chlorine.And two 2 atoms of hydrogen.

Explanation:

5 0
3 years ago
Significant figures are an indicator of the certainty in measurements true or false?
IRISSAK [1]
True. 

SF are used for simplifying figures in a measurement to produce a more accurate reading. 
3 0
3 years ago
An amphoteric salt is one that contains an anion that can act as either an acid or a base in water. Baking soda, NaHCO3, is an e
LenKa [72]

Answer:

pH = 8.34

Explanation:

The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:

H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>

<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>

Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:

pKa1 = 6.37; pKa2 = 10.32

As the pH of amphoteric salts is:

pH = (pKa1 + pKa2) / 2

<h2>pH = 8.34</h2>
3 0
3 years ago
Calculate the heat absorbed by the water in a calorimeter when 175 grams of lead cools from 125.0°C to 22.0°C. The specific heat
Iteru [2.4K]

Answer:

Q = 233.42 J

Explanation:

Given data:

Mass of lead = 175 g

Initial temperature = 125.0°C

Final temperature = 22.0°C

Specific heat capacity of lead = 0.01295 J/g.°C

Heat absorbed by water = ?

Solution:

Heat  absorbed by water is actually the heat lost by the metal.

Thus, we will calculate the heat lost by metal.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 22.0°C - 125.0°C

ΔT = -103°C

Q = 175 g × 0.01295 J/g.°C×-103°C

Q = -233.42 J

Heat absorbed by the water is 233.42 J.

5 0
3 years ago
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