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Rzqust [24]
3 years ago
12

Two asteroids in outer space collide, and stick together. The mass of each asteroid, and the velocity of each asteroid before th

e impact, are known. To find the momentum of the stuck-together asteroids after the impact, what approach would be useful?
(1) Use the Energy Principle.
(2) Use the Momentum Principle.
(3) It depends on whether or not the speed of the asteroids was near the speed of light.
(4) Use the relationship among velocity, displacement, and time.
(5) It depends on whether the collision was elastic or inelastic.
Physics
1 answer:
Naddik [55]3 years ago
7 0

Answer: (2) Use the Momentum Principle.

Explanation:

In fact, it is called the <u>Conservation of linear momentum principle,</u> which establishes the initial momentum p_{i} of the asteroids before the collision must be equal to the final momentum p_{f} after the collision, no matter if the collision was elastic or inelastic (in which the kinetic energy is not conserved).

In this sense, the linear momentum p of a body is defined as:

p=mV

Where m is the mass and V the velocity.

Therefore, the useful approach in this situation is<u> option (2)</u>.

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If you fired a rifle straight upwards at 1000 m/s, how far up will the bullet get?
nadya68 [22]

Answer:

h = 51020.40 meters

Explanation:

Speed of the rifle, v = 1000 m/s

Let h is the height gained by the bullet. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

h=\dfrac{v^2}{2g}

h=\dfrac{(1000\ m/s)^2}{2\times 9.8\ m/s^2}                    

h = 51020.40 meters

So, the bullet will get up to a height of 51020.40 meters. Hence, this is the required solution.          

4 0
3 years ago
Which clouds are often associated with thunder and lightning?
ehidna [41]
Your answer is cumulonimbus clouds
3 0
3 years ago
A disoriented physics professor drives 3.22 km north, then 4.75 km west, then 1.90 km south. find the magnitude and direction of
Andre45 [30]

It can be noted that the directions west and north are perpendicular to each other. hence we can use the right angle formula for calculating total distance in these directions. Also South is just negative north. This technique is called euclidean distance norm. It is the basis of Cartesian coordinate system.

Total distance = 3.22 N + 4.75 W +1.90  S

= 1.32 N + 4.75 W

D = \sqrt{N^2 + W^2}

D = 4.93 Km

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7 0
3 years ago
(d) What type of transformation is done by the following things?
mafiozo [28]

Answer:

human body is answer according to our studies

7 0
3 years ago
During which two time intervals does the particle undergo equal displacement?
san4es73 [151]

Answer:

BC and DE

Explanation:

In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.

Area under AB, d_1=\dfrac{1}{2}\times 2\times 10=10\ m

Area under BC, d_2=\dfrac{1}{2}\times 2\times 4=4\ m

Area under CD, d_3=\dfrac{1}{2}\times 2\times 7=7\ m

Area under DE, d_4=\dfrac{1}{2}\times 2\times 4=4\ m

Area under EF, d_5=\dfrac{1}{2}\times 2\times 3=3\ m

So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".

4 0
3 years ago
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