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3 years ago

What type of pollution did the Clean Water Act succeed in limiting?

Physics

2 answers:

Ilya [14]3 years ago

4 0

Sewage. If thats not it, then I need to see your choices. :)

lawyer [7]3 years ago

4 0

sewage is the answer because it's what the water was filled with most

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Does air defy gravity?

Andreyy89

Answer:

If you were to inject air into space what would have happen?

Explanation:

In order for air to defy gravity, it would require atmospheric pressure. But air dosen't defy gravity unless it has the support of atmospheric pressure.

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3 years ago

What were the patterns that people saw in the sky long ago?

Lena [83]

Long time ago, people saw the constellations as patterns in the sky. They names these patterns and tell stories about them. What people saw laong time ago are just mere patterns which forms animals and shapes. We got the names of our constellations from the Greeks who named the constellations after the mythological heroes and mythological legends.

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3 years ago

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VashaNatasha [74]

Two half lives so it is 4000 years old

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3 years ago

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The diagram shows a swinging pendulum.

pashok25 [27]

Answer:

A. The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.

Explanation:

took the quiz on edge

8 0

2 years ago

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I was driving along at 20 m/s, trying to change a CD and not watching where I was going. When I looked up, I found myself 45 m f

cricket20 [7]

Answer:

$a=4.44\frac{m}{s^2}$

Explanation:

First we have to find the time required for train to travel 60 meters and impact the car, this is an uniform linear motion:

$t=\frac{d}{v}\\\\t=\frac{60m}{30\frac{m}{s}}=2s$

The reaction time of the driver before starting to accelerate was 0.50 seconds. So, remaining time for driver is 1.5 seconds.

Now, we have to calculate the distance traveled for the driver in this 0.5 seconds before he start to accelerate. Again, is an uniform linear motion:

$d=vt\\d=20\frac{m}{s}(0.5s)=10m$

The driver cover 10 meters in this 0.5 seconds. So, the remaining distance to be cover in 1.5 seconds by the driver are 35 meters. We calculate the minimum acceleration required by the car in order to cross the tracks before the train arrive, Since this is an uniformly accelerated motion, we use the following equation:

$d=v_0t+\frac{1}{2}at^2\\a=\frac{2(d-v_0t)}{t^2}\\a=\frac{2(35m-20\frac{m}{s}*1.5s}{(1.5s)^2}\\a=4.44\frac{m}{s^2}$

7 0

3 years ago