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3 years ago

1. Distinguish between amplitude and frequency and give an example.

Physics

1 answer:

Svetlanka [38]3 years ago

5 0

Answer:

The difference between frequency and amplitude is that frequency is a measurement of cycles per second, and amplitude is a measurement of how large a wave is. Amplitude represents the wave's energy. Large waves contain more energy than small waves. For example, a sound wave with a high amplitude is perceived as loud.

Explanation:

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A good easy question for a science minded person!! 20 points for whoever answer

ss7ja [257]

Answer:

the answer is the first letter in the alphabet

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3 years ago

Objects fall near the surface of the earth with a constant downward acceleration of 10 m/s2 . At a certain instant an object is

anastassius [24]

Answer:

After 2 seconds the velocity of the object is 0 m/s.

Explanation:

The velocity at 2 seconds later can be calculated as follows:

$V_{f} = V_{0} - gt$

Where:

$V_{f}$ : is the velocity at 2 seconds

$V_{0}$ : is the initial velocity = 20 m/s

g: is the gravity = 10 m/s²

t: is the time = 2 s

Hence, the final velocity is:

$V_{f} = V_{0} - gt = 20 m/s - 10 m/s^{2}*2 s = 0 m/s$

This value (0 m/s) means that the object has reached the maximum height.

Therefore, after 2 seconds the velocity of the object is 0 m/s.

I hope it helps you!

6 0

3 years ago

The head of a rattlesnake can accelerate at 49 m/s2 in striking a victim. If a car could do as well, how long would it take to r

Anettt [7]

<h2>Time taken is 0.459 seconds</h2>

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Final velocity, v = 81 km/hr = 22.5 m/s

Time, t = ?

Acceleration, a = 49 m/s²

Substituting

v = u + at

22.5 = 0 + 49 x t

t = 0.459 seconds

Time taken is 0.459 seconds

3 0

4 years ago

An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.

noname [10]

The thermal efficiency is defined as follows

$\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}}$ ,

and the energy which is put into the system is

$Q_{\text{in}} = W_\text{out} + Q_\text{out}$ .

In your case $Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.$

So $Q_\text{out}=10 \text{ J}$ which gives an efficiency of

$\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%$ .

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3 years ago

What is the name of a variable that you change in an experiment

stealth61 [152]

Independent variable

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4 years ago

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