Answer:
The expression is equivalent to 4 square root 6 divided by 3 root 2 is:
8/3
Step-by-step explanation:
Given expression:
4 square root 6 divided by 3 root 2
![=\frac{4\sqrt{2*2^{2} }}{3\sqrt{2} }](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4%5Csqrt%7B2%2A2%5E%7B2%7D%20%7D%7D%7B3%5Csqrt%7B2%7D%20%7D)
square root of 2² = 2 hence,
Common terms in the numerator and denominator cancels each other out
![=\frac{8}{3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B8%7D%7B3%7D)
By solving the expression using simple mathematical rules, we got an equivalent expression of
![\frac{4\sqrt{6}}{3\sqrt{2} } = \frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Csqrt%7B6%7D%7D%7B3%5Csqrt%7B2%7D%20%7D%20%3D%20%5Cfrac%7B8%7D%7B3%7D)
Answer:
x ∉ R
Step-by-step explanation:
x² = - 21
if x² < 0 => x ∉ R
When you go into this problem, you want to figure out your marble ammount to 50 so in this case we will say C for color and 50 for the total ammount of marbles.
We know 15 are pink, 8 are black, 2 are green, 18 are clear, and 7 are striped
15P/50
8B/50
2G/50
18C/50
7S/50 for a total of 50 marbles
Now we use the chart to decide our awnsers
A. We know our propability of drawing a green and clear is 20/50 which if we simplify is a 2/5 ratio. If We put this in perspective 2/5 is rare and is unlikley to even.
B. We know a striped marble is 18/50 or 1.8/5 ratio which is mainly unlikely
C. We have 23/50 marbles that are black and pink, our propability is about 2.3/5 and gives us an even chance to get one of these
D. We know we have 33/50 marbles that are pink and clear and gives us a 3.3/5 chance of getting one of these and gives us an even to likely chance of getting one of these.
E. If we have a total of 17 marbles in these 3 colors, we have a 1.7/5 chance of getting one of these and is probably impossible to unlikey.
To rearrange you must first simplify
aq-ac=d
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
2 n/3 would be the closest answer although it looks as if the 2 is supposed to be multiplied by n/3 which would lead me to write it as 2(n/3)