Question

HELP - WILL MAKE BRAINLIEST IF CORRECT - a chunk of lava flies out of a volcano from a height of 12,447 feet a velocity of 608 feet per second. Find the highest point the lava reaches and how long it takes to reach it using the equation y= -16t^2 + 608t + 12,447.

Answer 1

Answer:

18,223 feet

Step-by-step explanation:

y= -16t^2 + 608t + 12,447.

y = -16(t² - 38t) + 12447

y = -16[t² - 2(t)(19) + 19² - 19²] + 12447

y = -16(t - 19)² - 16(-19²) + 12447

y = -16(t - 19)² + 18223

Vertex: (19, 18223)

Max height is 18,223 at t = 19

Answer 2

The parabolas are:

a = -16

b = 608

c = 12,447

x_v = -b/2a

t_v = -608/2(-16)

t_v = -608/-32

t_v = 19

Plug in t_v = 19 to find y_v

y = -16(19)^2 + 608(19) + 12,447

y = -16(361) + 11,552 + 12,477

y = -5,776 + 11,552 + 12,477

y = 18,253

We have the point (19, 18,253)

The max height is at 18,253 when t = 19

Best of Luck!