Answer:
18,223 feet
Step-by-step explanation:
y= -16t^2 + 608t + 12,447.
y = -16(t² - 38t) + 12447
y = -16[t² - 2(t)(19) + 19² - 19²] + 12447
y = -16(t - 19)² - 16(-19²) + 12447
y = -16(t - 19)² + 18223
Vertex: (19, 18223)
Max height is 18,223 at t = 19
The parabolas are:
a = -16
b = 608
c = 12,447
x_v = -b/2a
t_v = -608/2(-16)
t_v = -608/-32
t_v = 19
Plug in t_v = 19 to find y_v
y = -16(19)^2 + 608(19) + 12,447
y = -16(361) + 11,552 + 12,477
y = -5,776 + 11,552 + 12,477
y = 18,253
We have the point (19, 18,253)
The max height is at 18,253 when t = 19
Best of Luck!
Answer:its 11.55
also 108°
2, 4, 6 and 8 are the angles
an the other group of same angles is 1, 3, 5 and 5
x = 3; y = 2
You would just set each side equal to its opposite so for x, it'll be like:
4x+6=7x-3
and for y:
4y-3=3y+1
I attached my work below as well to help you.
solve with algebraic method: 3x^2+10x=8. Solution- x = 2/3 x = -4
1/100 (1471 z + 2100)
0.01 (1471 z + 2100) the result I got
and the Factorization over the splitting field:
14.71 z + 21