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2 years ago

I can someone how to do this plzzz

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

5 0

Its D .HOPE IT HELPS !

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Find x and the measure of each side.

Anna71 [15]

Answer:

x=27.5

FG=72.5

GH=60

HF=47.5

Step-by-step explanation:

Sum of angles in a triangle=180

Therefore, FG+GH+HF=180

Substituting the values we have,

(3x - 10) + (2x+5) +(x+20) = 180

Collecting like terms

3x+2x+x = 180 +10 - 5 - 20

6x = 165

X= 27.5

FG = (3x - 10) = 3(27.5) - 10

FG= 72.5

GH= (2x+5) = 2(27.5)+5

GH=60

HF= x+20 =27.5+20

HF=47.5

5 0

10 months ago

dentify the vertical asymptotes of f(x) = quantity x plus 6 over quantity x squared minus 9x plus 18.

ser-zykov [4K]

So the function we're dealing with is

f(x) = $\frac{x+6}{x^{2}-9x+18 }$

Factorising we get, $x^{2} -9x+18=0$
$(x-3)(x-6)=0$

Therefore, the vertical asymptotes are at x = 3 and x = 6

8 0

2 years ago

Estimate of 403,446 and 396, 755?

vesna_86 [32]

The sum of those is 800,201

4 0

2 years ago

Please help solve quick

RoseWind [281]

Answer:

see below

Step-by-step explanation:

3x^2 + 17x +10 =0

(3x+ ) ( x+ ) =0

We need to factor 10 = 2*5 or 1*10

They are positive since we have all positive terms

3*5 = 15+2 = 17

The 5 needs to multiply the 3 so it goes on the outside

(3x+ ) ( x+ 5 ) =0

That leaves the 2 on the inside

(3x+ 2 ) ( x+ 5 ) =0

Using the zero product property

3x+2 =0 x+5=0

3x = -2 x=-5

x = -2/3 x = -5

5 0

2 years ago

A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i

Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: $\frac{x}{20}+\frac{x}{12}+900= 1200$ , where x is the distance.

B. The flowerbed is 2250 feet far from the hive.

<u><em>Explanation</em></u>

Suppose, the distance of the flowerbed from the hive is $x$ feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, $Time=\frac{Distance}{Speed}$

So, the time taken by the bee to reach the flowerbed $= \frac{x}{20}$ seconds and the time taken to fly back to the hive $=\frac{x}{12}$ seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

$\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250$

Thus, the distance of the flowerbed from the hive is 2250 feet.

5 0

2 years ago