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MA_775_DIABLO [31]
3 years ago
11

a private school admits no more than 100 students every year. additionally, at least 30 of these students must be girls, and the

school admits at least as many girls as boys. What are the equation to this word problem
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0
2/2 part of the equation is ≤ B
maybe       30/100 ≤ B
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A railway engine is of mass 72tonnes and 11m long. An exact scale model is made of it and is 44cm long. find the mass of the mod
34kurt

Answer:

it is correct

Step-by-step explanation:

2000 N

The resistance force acting is 1N per ton.

Tension in the coupling between engine and the wagon is 2000N.

4 0
3 years ago
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2x^2+7x-3

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Check the image

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Is 8,2,1/2,1/8 exponential or not
Anvisha [2.4K]

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3 years ago
Write the sentence as an inequality. The cost of a ticket t will be no more than $52.
NeX [460]

Answer:

t is less than or equal to $52, or t <= $52

Step-by-step explanation:

If you can't have more than $52, then use less than symbol (<). The sentence doesn't state that a ticket shouldn't cost $52, so it's safe to assume that you can have exactly $52.

5 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
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