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Rus_ich [418]
3 years ago
6

How many measurements are less than 2 2/4 inches?

Mathematics
1 answer:
patriot [66]3 years ago
8 0
Centimeter
Milimeter
Micrometer
Nanometer
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Leticia babysat on Saturday for 5 hours. She already babysat for 4 hours which makes it (8 x 4) =$32 But she earned $72 so the rest $40 / 8 =5 hours 
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3 years ago
WHAT IS THE LINE OF BEST FIT FOR THE FOLLOWING DATA (1,3) (2,0) (5,-8) (9, -25) . WRITE YOUR ANSWERS IN THE FORM OF Y= AX+ B​
dimulka [17.4K]

Answer:

3.471 + 7.2516 x

Step-by-step explanation:

Given the data:

(1,3) (2,0) (5,-8) (9, -25) .

X:

1

2

5

9

Y:

3

0

-8

-25

The line of best fit for the data given can be obtained using an online regression calculator :

The equation of best fit for the data is thus;

Best fit equation; y = -3.471 + 7.2516x

Intercept = - 3.471 ;

Slope = 7.2516

5 0
3 years ago
Help please with my homework assignment asap!!
nirvana33 [79]
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4 0
3 years ago
2.38+4.89=3+ _ <br><br>changing expressions??
Lerok [7]
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3 0
3 years ago
Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0
3 years ago
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