Which of the following is the graph of y = negative 4 StartRoot x EndRoot? On a coordinate plane, an absolute value curve opens
down and to the right in quadrant 1 and starts at (0, 0). On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at (0, 0). On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4 and starts at (0, 0). It goes through (5, negative 2). On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4 and starts at (0, 0). It goes through (5, negative 9).
2 answers:
Answer:
see the procedure
Step-by-step explanation:
we have
we know that
The domain of a function is the set of all possible values of x
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
In this problem
The domain for x is the interval [0,∞)
All real numbers greater than or equal to zero
The range for y is the interval (-∞,0]
All real numbers less than or equal to zero
The graph in the attached figure
therefore
On a coordinate plane, an absolute value curve opens down and to the right in quadrant 4 and starts at (0, 0)
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I think that's what you mean
<u>Answer: </u>
The value of the exponential expression is 2
<u>Solution:</u>
16 superscript one-fourth=
As per the problem,
We have to find the value of
16 in terms of 2 can be written as
=
=
As per the exponential rule,
=
Here,
=
= 2
Hence, the value is 2.