Question

Which of the following is the graph of y = negative 4 StartRoot x EndRoot? On a coordinate plane, an absolute value curve opens down and to the right in quadrant 1 and starts at (0, 0). On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at (0, 0). On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4 and starts at (0, 0). It goes through (5, negative 2). On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4 and starts at (0, 0). It goes through (5, negative 9).

Answer 1

Answer:

see the procedure

Step-by-step explanation:

we have

$y=-4\sqrt{x}$

we know that

The domain of a function is the set of all possible values of x

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

In this problem

The domain for x is the interval [0,∞)

All real numbers greater than or equal to zero

The range for y is the interval (-∞,0]

All real numbers less than or equal to zero

The graph in the attached figure

therefore

On a coordinate plane, an absolute value curve opens down and to the right in quadrant 4 and starts at (0, 0)

Answer 2

Answer:

d

Step-by-step explanation:

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