Question

A plane is flying horizontally with speed 167 m/s at a height 4040 m above the ground, when a package is dropped from the plane. The acceleration of gravity is 9.8 m/s 2 . Neglecting air resistance, when the package hits the ground, the plane will be:

Answer 1

Answer:

The plane will be 4795.23 meters from where he threw the package.

Explanation:

Data:

v = 167 m/s

h = 4040 m

g = 9.8m/s²

package:

after it is dropped there is no horizontal force, so...

$X - Xo = Vt$

t = $\frac{X - Xo}{V}$  I

in the vertical we have only $P = mg$

$Y - Yo = Vot -\frac{gt^{2} }{2}$ but Vo = 0 because the package is dropped

$Y - Yo =-\frac{gt^{2} }{2}$  II

replacing I in II

$Y - Yo =-\frac{g(X - Xo)^{2} }{2V^{2}}$

$0 - 4040 =-\frac{9.8(X - Xo)^{2} }{2*167^{2}}$

X - Xo = 4795.23

The distance from where the plane drops the package and where it hits the ground is the same as the plane flies horizontally, as there is no acceleration at x.