In this situation, both of the vehicles turn towards starboard.
By turning to the starboard, or right, side, the vehicles are able to avoid collision. Because waterways are not marked in a manner like roads are, it is necessary to place such conventions of turning in situations where vehicles approach one another head on. If a convention was not in place, the risk of collision would be many times greater. For example, the motorboat operator may turn left, while the PWC operator turns right, resulting in a collision.
The speed of the ball after one second is obtained as 9.8 m/s.
<h3>What is the speed after 1 second?</h3>
We know that since the ball dropped from a height, its initial velocity is zero.
Thus we have;
u = 0 m/s
v = ???
g = 9,8 m/s²
t = 1sec
Given that;
v = u + at
v = at
v = 9,8 m/s² * 1sec
v = 9.8 m/s
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Just divide the two numbers
Answer:
T=12544 N*m
Explanation:
Given
L=4.0m
ms=500kg
mw=70kg
Torque is the force in a distance the relation is proportional so the torque of weight first is:
Ts = Fs*d
Ts = ms*g*L
Ts = 500kg*9.8m/s^2*2m
Ts = 9800 N*m
now torque of the worker
Tw = Fw*d
Tw = 70kg*9.8m/s^2*4m
Tw = 2744 N*m
Torque net is
Tnet = Tw+Ts
Tnet= 2744 + 9800 =12544 N*m
Answer:
I believe the answer is A.