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The frequency of sodium light in vacuum is 5 ×
Hz.
Answer:
Option e
Explanation:
It is known that frequency of a wave is inversely proportional to the wavelength of the wave. And the proportionality constant is the speed of light in vacuum. As the speed of light in vacuum is known as 3×
m/s and the wavelength of the light in vacuum is given as 6 ×
m, then the frequency of the light is determined as
Frequency = Speed of light in vacuum/Wavelength of light
Frequency = 
Frequency = 0.5×
= 5 ×
Hz.
So the frequency of sodium light in vacuum is 5 ×
Hz.
Answer:
988.39 N/C
Explanation:
First, we start by finding the magnitude of the electric dipole moment, as it's going to be needed
p = 4.40*10^-9 * 3.10*10^-3
p = 1.364*10^-11 Cm
The charges are in a uniform electric field E whose direction makes an angle of 36.4° with the line connecting the charges.
Magnitude of torque exerted on the dipole,
t = 8.0×10−9 N.m
pEsinO = t, making E subject of formula
E = t / psinO
E = 8.0*10^-9/1.364*10^-11 (sin36.4)
E = 8.0*10^-9/1.364*10^-11 * (0.5934)
E = 8.0*10^-9 / 8.094*10^-12
E = 988.39 N/C
the magnitude of this field is E = 988.39 N/C