Ask question

Ask question

All categories

3 years ago

8

A baseball has a mass of 0.145 kilograms, and a bowling ball has a mass of 6.8 kilograms. What is the gravitational force betwee

n them if their centers are 0.5 m apart?

2 answers:

Olegator [25]3 years ago

6 0

Quite low

Gravitation force = $\frac{6.67* 10^{-11}*0.145*6.8 }{ 0.5^{2} }$ = 26.3 * $10^{-11}$ = 2.63 * $10^{-10}$ N

cestrela7 [59]3 years ago

5 0

2.6 × 10^-10

(The answer is C)

You might be interested in

A point charge of 5.7 µC moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mT, as shown in the diagram

Nataly_w [17]

Answer:

$6.6\cdot 10^{-3} N$

Explanation:

The magnitude of the magnetic force acting on the charge is given by

$F=qvB sin \theta$

where

$q=5.7 \mu C = 5.7 \cdot 10^{-6} C$ is the magnitude of the charge

$v=4.5\cdot 10^5 m/s$ is the velocity of the charge

$B=3.2 mT = 0.0032 T$ is the magnitude of the magnetic field

$\theta = 90^{\circ}-37^{\circ} =53^{\circ}$ is the angle between the directions of v and B

Substituting the numbers into the equation, we find:

$F=(5.7\cdot 10^{-6})(4.5\cdot 10^5)(0.0032)(sin 53^{\circ})=6.6\cdot 10^{-3} N$

8 0

4 years ago

Read 2 more answers

6 latter word and it has a s and a I and it has mass (9.______________liquids, and gases all have mass.)

Firdavs [7]

Answer:

Solids

Explanation:

Solids, liquids, and gases all have mass.

7 0

2 years ago

A sound wave is moving through air. The wave has a wavelength of 0.65 m and a frequency of 512 Hz. Calculate the speed of the wa

nexus9112 [7]

Answer:

"332.8 m/s" is the right solution.

Explanation:

The given values are:

Wavelength,

$\lambda=0.65 \ m$

Frequency,

$f = 512 \ Hz$

As we know,

⇒ $Speed=Frequency\times Wavelength$

or,

⇒ $V=f\times \lambda$

By putting the given values in the above relation, we get

⇒ $=512\times 0.65$

⇒ $=332.8 \ m/s$

6 0

3 years ago

Take some time to research a utility plant. If there is one in your area, you may even visit it. Otherwise, look up a type of pl

LenaWriter [7]

Answer:

bro we cant do this

Explanation:

7 0

3 years ago

A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it

SashulF [63]

Answer:

$2.4\sqrt{L}$ where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

$gsin\theta = 9.81 sin17^o = 2.87 m/s^2$

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

$v^2 - v_0^2 = 2a\Delta s$

where v m/s is the final velocity, $v_0$ = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and $\Delta s = L$ is the distance traveled:

$v^2 - 0 = 2*2.87*L$

$v = \sqrt{5.74L} = 2.4\sqrt{L}$

6 0

3 years ago