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Bas_tet [7]
3 years ago
14

A child has 11 stuffed animals. How many ways can she choose 3 animals to take along with

Mathematics
2 answers:
Leto [7]3 years ago
5 0

Step-by-step explanation:

se can take 3 3 3 4 times for each animal that is stuffed in different baga

Lina20 [59]3 years ago
5 0

Answer:

165 ways

Step-by-step explanation:

\binom{n}{m}

That notation is read "n choose m", and it indicates the number of ways one can choose m objects from a collection of n objects, if we don't care about "order".

So in your case we have

\binom{11}{3}

which in terms of a "factorial" notation is

11! / 3! × (11-3)!

11×10×9×8! / 3! × 8!

990 / 3

165

I've just assumed that you know what factorial means. If you don't, feel free to ask me.

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