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Elenna [48]
3 years ago
10

Assume you have collected data pairs (x, y) on a certain variety of tree. x is the number of weeks since the tree was planted an

d y is the height of the tree in inches. A plot of the data points with the best-fit line is given below. What age is predicted by the best-fit line for a height of 70 inches? 

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0
50 weeks is the age predicted by the best-fit line
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What is the slope of the line that goes through the points (1,-5) and (4,1)?
lesya692 [45]

Answer: m = 2

Step-by-step explanation:

What we know:

  • The slope needs to pass through the points (1, -5) and (4, 1)
  • There are 4 potential slopes given to us- only one is correct
  • We need to find the slope and make sure it is an option

How to solve:

By using the slope equation and the two points given to us, we can calculate the slope.

Process:

  • Set up equation                                                 (y2 - y1) / (x2 - x1)
  • Substitute                                                            (1 +5 ) / (4 - 1)
  • Simplify                                                                6 / 3
  • Simplest form                                                      2/ 1 =

Slope =                                                                          2

Solution: m = 2

4 0
2 years ago
What does -6(-7 - 3k)
Zina [86]
Here, Just apply Distributive property which tells, a(b + c) = ab + bc
So, -6(-7 - 3k) = 42 + 18k

In short, Your Answer would be 42 +18k

Hope this helps!
4 0
2 years ago
A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is 49\ ft

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

h(t)=-16t^{2} +63t+4

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

h(3)=-16(3)^{2} +63(3)+4=49\ ft

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

h(t)=-16t^{2} +63t+4

Group terms that contain the same variable, and move the constant to the opposite side of the equation

h(t)-4=-16t^{2} +63t

Factor the leading coefficient

h(t)-4=-16(t^{2} -(63/16)t)

Complete the square. Remember to balance the equation by adding the same constants to each side

h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})

h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})

Rewrite as perfect squares

h(t)-(67,600/1,024)=-16(t-(63/32))^{2}

h(t)=-16(t-(63/32))^{2}+(67,600/1,024)

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

h(t)=-16t^{2} +63t+4

For h(t)=0

0=-16t^{2} +63t+4

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0
3 years ago
How much gift paper is required to at least fully cover a
mestny [16]

Answer:

Step-by-step explanation:

Discussion

Where does that 682 come from? It cannot be the surface area of a cube with a side of 50 inches.

The edge length is 50 inches, so s = 50

SA = 6 * 50^2

SA = 15000 in^2

Answer: So at the very minimum, you need <u>15000</u> square inches of wrapping paper.

4 0
2 years ago
HELP!!
Sergio [31]
It would end up being 2 dollars and 45 cents
6 0
2 years ago
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