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AlekseyPX
3 years ago
14

150 minutes per day = hours per week

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
150 minutes / day for a week
= (150 minutes / day) * (7 days / week)
= 150 * 7 minutes / week
= 1050 minutes / week

(1050 minutes / week) * (1 hour / 60 minutes)
= (1050 / 60) hours / week
= (105 / 6) hours / week
= 17.5 hours / week

You could also convert to hours first. 150 minutes = 2.5 hours * 7 days = 17.5 hours per week.
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Answer:

the answer is C

Step-by-step explanation:

The answer is C.

Because we do not have any tables graphs etc., we can only use the fact that the range is 1

The definition of range is the difference between the largest amount and the smallest amount. In equation form, it should look like this:  

Now lets move to the answer choices:

Answer A. is wrong

If everyone surfed for exactly an hour, the largest amount of time would be 1 hour and the smallest amount of time would also be 1 hour. Put this into the equation and the range would be 0 which is contradicted from the data present

Answer B. is wrong because the range is not the average, the mean is the average. We are looking for the range, not the mean so Answer B. is incorrect.

Answer C. is correct. The range is the difference between the largest and the smallest. In this answer, it tells us that the range is the difference between the greatest amount of time and the least amount of time spent surfing the Internet is 1 hour. This follows the term of "Range" and therefore, Answer C. is correct.

Answer D. is incorrect because the range does not have anything to do with quotients.(By the way, a quotient is the result of dividing a dividend with a divisor.) The range is only obtainable with subtraction, not division, so answer D. is incorrect.

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3 years ago
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Answer: x(t) = 5cm*cos(t*pi/2s)

Step-by-step explanation:

This is a sinusoidal equation, so we can write this as:

x(t) = A*cos(c*t + p)  + B

where B is the axis around the movement, as the resting position is x = 0, we have B = 0

so x(t) = A*cos(c*t + p)

A is the amplitude of the oscilation, c is the frequency and p is a phase.

We know that when t = 0s, we have x(2s) = 5cm

if this is the maximum displacement, then knowing that the maximum of the cosine is cos(0) = 1

then we must have that p = 0

x(0s) = A*cos(0) = 5cm

then we have A = 5cm

Now, when t = 2s, we have:

x(2s) = 5cm*cos(2s*c) = -5cm

then 2s*c is the minimum of the cos(x) function, this is:

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then 2s*c = pi

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