First identify which is being oxidized and reduced. In this case, the Mg is being oxidized and the Hg is being reduced.
Mg --> Mg+2
<span>Hg+2 --> Hg+1
</span>
Then you have to balance each half reaction first with electrons before adding them together in one equation

⇒

and

⇒
and then combine them together to form

⇒

It isn't necessary to keep the electrons but its essential to know how many there are in order to know how many are in the equation in order to calculate the reaction energy. Note: A<span>dd H+ and H2O to balance the H's and O's in acidic solution if needed.</span>
Answer:
if charge of ion is positive then it will loose electron
if charge of ion is negative it will gain electron
Answer:
Acid-base
Explanation:
KOH is a strong base, and NH₄Cl is an acid. They react to form a salt and water.
KOH + NH₄Cl ⟶ NH₃ + KCl + H₂O
base acid salt water
Answer:
There are 146 neutrons in Uranium-238
There are 90 electrons in Thorium-234
Sulfuric acid is prepared industrially by means of the response of water with sulfur trioxide which in turn is made by way of a chemical combination of sulfur dioxide and oxygen both by way of the touch system or the chamber system.
H2SO4 (l) H2O (g) + SO3 (g).
The reaction is highly exothermic as an enormous amount of heat is liberated.
The usual approach is to dilute the sulfur trioxide in sulphuric acid. This produces oleum. SO3 (g) + H2SO4 → H2S2O7 (1) Oleum can be in addition diluted in water to acquire concentrated sulphuric acid.
An acid catalyst is added to protonate the carbonyl carbon. How does this catalyze the response, robust acid catalysts catalyze the hydrolysis and transesterification of esters which enables the mechanism with a view to boom the electrophilicity of the carbonyl carbon to assist protonate the carbonyl oxygen.
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