Answer:
Explanation:
exothermic reactions are the reactions which involve the release of energy.
the energy released can be of any forms ,for example heat,light .
all the combustion reactions are exothermic reactions
The pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.
<h3>How to calculate pressure?</h3>
The pressure of an ideal gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
According to information in this question;
- T = 25°C = 25 + 273 = 298K
- V = 244.6mL = 0.24L
- R = 0.0821 Latm/Kmol
P × 0.24 = 1 × 0.0821 × 298
0.24P = 24.47
P = 24.47/0.24
P = 101.94atm
Therefore, the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.
Learn more about pressure at: brainly.com/question/11464844
Answer:
<em><u>V = 25 m/s</u></em>
Explanation:
From first equation of motion, V = U + at
V = 10 + ( 5×3 )
V = 25 m/s
<u>Answer:</u> The pH value of the solution is 10 and the solution is basic in nature.
<u>Explanation:</u>
To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
![[OH^-]=1\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1%5Ctimes%2010%5E%7B-4%7DM)
Putting values in above equation, we get:

To calculate pH of the solution, we use the equation:

There are three types of solution: acidic, basic and neutral
To determine the type of solution, we look at the pH values.
- The pH range of acidic solution is 0 to 6.9
- The pH range of basic solution is 7.1 to 14
- The pH of neutral solution is 7.
As, the pH of the solution is 10 and is lying in the range of basic solution, so the solution is basic in nature.
Answer:
t=(70)ln(19.9/20)/-ln2
70 is the years. 19.9 kg is what is left after 0.1kg decay. 20kg is your initial amount.
t=0.506 years with a decay constant of 0.0099021/year
Explanation: