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arlik [135]
3 years ago
13

What is the surface area of this solid?

Mathematics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

SA. = 62.8 +87.92= 150.72

Step-by-step explanation:

surface area of cone without base = pi*r*s = 3.14 * 2* 10 = 62.8

Surface area of cylinder without base = 2*pi*r*h + pi*r*r

                                                               = 2* 3.14 * 2 * 6 + 3.14*2*2

                                                               = 75.36 + 12.56 = 87.92

SA. = 62.8 +87.92= 150.72

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boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation h=-16t^2+24t+16, where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation h=-16t^2+24t+16, we get,

0=-16t^2+24t+16

Switch sides, we have,

-16 t^{2}+24 t+16=0

Let us solve the equation using the quadratic formula.

Thus, we have,

t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}

Simplifying, we get,

t=\frac{-24 \pm \sqrt{576+1024}}{-32}

t=\frac{-24 \pm \sqrt{1600}}{-32}

t=\frac{-24 \pm 40}{-32}

Hence, the two values of t are

t=\frac{-24 + 40}{-32}   and   t=\frac{-24 -40}{-32}

Simplifying the values, we get,

t=\frac{16}{-32}  and  t=\frac{-64}{-32}

Dividing, we get,

t=-\frac{1}{2}  and  t=2

Since, t cannot negative values, we have,

t=2

Thus, the rock will hit the ground at 2 seconds.

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Please help me check my work and correct me if I'm wrong.
Aleonysh [2.5K]
I believe you are right with all of them.
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Answer:

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Step-by-step explanation:

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