The limiting reactant is determined by the supply and stoichiometric equation.
<h3>Limiting reactants</h3>
They are reactants that are limited in availability, and thus, determine how far reactions can go in terms of producing products.
In a reaction involving magnesium and hydrochloric acid to produce hydrogen gas as follows:
The number of moles of HCl is twice that of Mg. Thus, if both reactants are supplied in the required proportion, no reactant will be limiting.
However, if the number of moles of HCl supplied is not up to twice that of Mg, HCl will become limiting. Also, if the amount of Mg supplied is not equal to half of that of HCl supplied, Mg will be limiting.
More on limiting reactants can be found here: brainly.com/question/14225536
#SPJ1
The amount of heat that could be removed by 20.0 g of ethyl chloride is 8.184 kJ.
<h3>How do we calculate required heat?</h3>
Required amount of heat which can be removed for the vaporization will be calculated as:
Q = (n)(ΔHv), where
- n = moles of ethyl chloride
- ΔHv = heat of vaporization = 26.4 kj/mol
Moles will be calculated as:
n = W/M, where
- W = given mass of ethyl chloride = 20g
- M = molar mass of ethyl chloride = 64.51 g/mol
n = 20 / 64.51 = 0.31 mol
On putting all these values in the above equation, we get
Q = (0.31)(26.4) = 8.184 kJ
Hence involved amount of heat is 8.184 kJ.
To know more about heat of vaporization, visit the below link:
brainly.com/question/13106213
#SPJ4
I think it is because it has an even number of valence electrons.
I believe the answer is 3
The molecules of Li₂O that would produce if you used up 6 atoms of Li(s) is 3.
<h3>What is Lithiumdioxide?</h3>
It is an unstable inorganic and radical compound, used in the manufacture of glass and ceramic.
The balanced equation
If the atoms of lithium moves up to 6 the lithium oxide molecules will be 3, as you can see in the equation.
Thus, the molecules of Li will be 3.
Learn more about lithium dioxide
brainly.com/question/3487113
#SPJ1
