Answer:
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
Explanation:
Al₂O₃ → Aluminum oxide
We determine the molar mass:
Molar mass Al . 2 + Molar mass O . 3
27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
Answer:
Salt
Explanation:
It is because it has a defined composition.
Answer:
how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?
(A) n=m/M,
n(Al)=5.4/27=0.2 moles
n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles
Number of oxygen atoms= n(O2)*Avogadro's number
=0.15*6.02*10^23=9.03*10^22 oxgyen atoms
(B)
n=m/M
n(Al)=0.6/27=0.02222 moles
n(O2)=n(Al)*3/4=0.016666 moles
m=n*M
m(O2)=0.0166666*32=0.53333 grams
You get purple or magenta by mixing red and blue
Answer:
Photic Zone
Explanation:
The photic zone is the uppermost layer of the sea that recieves sunlight allowing phytoplankton to perform photosynthesis.
