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Murljashka [212]
4 years ago
11

Please help me solve this

Mathematics
1 answer:
yuradex [85]4 years ago
4 0
Replace y with x: 10x-9(x-2)=24
10x-9x+18=24
x=6
y=x-2=6-2=4
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I'm not sure how to simplify this expression with the exponents rules of multiplication
Vedmedyk [2.9K]
The rule of exponential multiplication is (a^x)*(a^y)=a^(x+y)
using this with your expression, we can do
(10^1)*(10^3)*(10^2)=10^(1+3+2)=10^6
Final answer:
10^6 or 1 million
Hope I helped :)
3 0
3 years ago
How to multiply 18 3/8 x 1/4
user100 [1]
Decimal Form: 
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</span>
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<span>147/32</span><span> 

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4 0
3 years ago
Read 2 more answers
12. If 5t + 2 = 6, then t =
tankabanditka [31]
It would be t=0.8, mainly bc you subtract two from six , that reduces it to four 
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6 0
4 years ago
Read 2 more answers
A box contains 8 two-inch screws. Four have a Phillips head and 4 have a slotted head. In how many ways can 4 screws be chosen s
hammer [34]

Answer:

There are 6\cdot 6=36 different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

Step-by-step explanation:

If 4 screws must be chosen so that 2 have a Phillips head and 2 have a slotted head, then you have to choose 2 screws with a Phillips head from 4 screws with a Phillips head and 2 screws with a slotted head from 4 screws with a slotted head.

You can choose 2 screws with a Phillips head from 4 screws with a Phillips head in

C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6

different ways.

You can choose 2 screws with a slotted head from 4 screws with a slotted head in

C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6

different ways.

In total there are 6\cdot 6=36 different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

7 0
3 years ago
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