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3 years ago

I just need number 10 .

Mathematics

2 answers:

Inessa [10]3 years ago

8 0

You multiply 11 by 6 so it's 66 then add 1 and it's 67. Then you put 67 over 6. Answer: 67 over 6

Gnoma [55]3 years ago

5 0

A mixed number ? Wouldn't you have to multiply 11 x 6 which equals 66 + 1 = 67 ? Thats how they taught me in elementary school .

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US National forest cover approximately 300,000 square miles. conversationalist want the total square footage of forests to be 30

Sveta_85 [38]

E+10 is equivalent to 10^10 so, 9e+10 is equivalent to 9*10^10. 300,000^2 is 90000000000 square miles, where as the US has 4000000. Therefore, if the national forest were as large as the environmentalist wants them to be, the forest would be larger than the US, which is IMPOSSIBLE !!! As a result, this goal is not reasonable

7 0

3 years ago

WHAT IS THE LINE OF BEST FIT FOR THE FOLLOWING DATA (1,3) (2,0) (5,-8) (9, -25) . WRITE YOUR ANSWERS IN THE FORM OF Y= AX+ B

dimulka [17.4K]

Answer:

3.471 + 7.2516 x

Step-by-step explanation:

Given the data:

(1,3) (2,0) (5,-8) (9, -25) .

-8

-25

The line of best fit for the data given can be obtained using an online regression calculator :

The equation of best fit for the data is thus;

Best fit equation; y = -3.471 + 7.2516x

Intercept = - 3.471 ;

Slope = 7.2516

5 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago

Why is circle 1 similar to circle 2

Kobotan [32]

Your answer is letter A.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

A botanist was measuring how tall her plant grew. After two weeks it had grown 12.93 inches.The second week alone it had grown 3

Korolek [52]

Answer:

9.5 inches

Step-by-step explanation:

The relationship is presumed to be ...

(first week's growth) + (second week's growth) = (growth in two weeks)

(first week's growth) + 3.43 inches = 12.93 inches . . . . . fill in the numbers

Subtract 3.43 from both sides of the equation:

first week's growth = 12.93 inches - 3.43 inches

first week's growth = 9.50 inches

The plant grew 9.50 inches in the first week.

6 0

3 years ago