Question

The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 mc022-1.jpg 1023 atoms in 1 mol. How many atoms are present in 48.60 g of Mg?

Answer 1

48.60g Mg x (1 mol Mg /24.3g Mg) x (6.02x10^23) = 1.20x10^24

Answer 2

Answer: $1.204\times 10^{24} atoms$ of magnesium are present 48.60 grams of magnesium.

Explanation:

Molar mass of the magnesium = 24.30 g/mol

Given mass of the magnesium = 48.60 g

$moles=\frac{\text{Given mass}}{\text{molar mass}}$

Moles of magnesium = $\frac{48.60 g}{24.30 g/mol}=2 mol$

$1 mol=6.02\times 10^{23} atoms$

Number of a magnesium atoms in 2 moles:

$2\times 6.02\times 10^{23}=1.204\times 10^{24} atoms$

$1.204\times 10^{24} atoms$ of magnesium are present 48.60 grams of magnesium.