Answer:
C: The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts
Explanation:
Looking at the options, the correct one is Option C because the actual yield usually depends on the conditions of the reaction, while the theoretical yield usually varies with only the amount of reactant.
Answer:
Explanation:
Hello.
In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:
Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:
Best regards.
Answer:
induced dipole-dipole forces or London Dispersion forces / van der Waals forces.
Explanation:
Hexane is non-polar in nature. This is due to :
The bond in the molecule is C-H, which is non-polar in nature because the carbon and the hydrogen having very similar electronegativity values.
Hexane is also symmetric.
The intermolecular force acting in the molecule of the hexane are induced the dipole-dipole forces or London Dispersion forces / van der Waals forces.
Answer:
9.01%
Explanation:
The following data were obtained from the question:
Mass of sodium nitrate, NaNO3 = 56.5g
Mass of solution = 627g
The percentage composition of sodium nitrate, NaNO3 in the solution can be obtained as follow:
Percentage composition of NaNO3 = Mass of NaNO3/mass of solution x 100
Percentage composition of NaNO3 = 56.5/627 x 100 = 9.01%
Therefore, the percentage composition of sodium nitrate, NaNO3 in the solution is 9.01%
