All categories

2 years ago

What is the [OH-],[H3O] and PH for the following

Chemistry

1 answer:

malfutka [58]2 years ago

4 0

The values for hydroxide ions, hydronium ions and pH are found in the attached picture.

Explanation:

See the attached picture.

Learn more about:

brainly.com/question/1525823

#learnwithBrainly

You might be interested in

The complementary base sequence to GTAGCT is:_______.A) CATCGA.B) ACGATC.C) GCAGTA.D) AGTCGA.E) None of the above

IceJOKER [234]

Answer:none of the above

Explanation:

8 0

2 years ago

It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta

Zigmanuir [339]

Answer:

$\lambda=241.9\ nm$

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,

1 mole = $6.023\times 10^{23}\ electrons$

So,

$6.023\times 10^{23}$ electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of $\frac {495.0}{6.023\times 10^{23}}\ kJ$ of energy.

Energy required = $82.18\times 10^{-23}\ kJ$

Also,

1 kJ = 1000 J

So,

Energy required = $82.18\times 10^{-20}\ J$

Also, $E=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

So,

$79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}$

$\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}$

$\lambda=\frac{19.878}{10^6\times \:82.18}$

$\lambda=2.4188\times 10^{-7}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=241.9\ nm$

6 0

2 years ago

El compuesto es soluble en agua y conduce la eletricidad

salantis [7]

Answer:

creo que si

Explanation:

por que si vienes a ver has un experimento con agua y electricidad. por eso es que el compuesto es soluble en agua y conduce la electricidad

6 0

2 years ago

I GIVE BRAINLIEST TO WHO EVER GETS IT RIGHT!

Gala2k [10]

Answer: B. Bohr and D. Rutherford

6 0

2 years ago

Please help I need a 100!!!

Salsk061 [2.6K]

Its in vertical columns. I hope this helps and you get a 100 on your test!

6 0

3 years ago

Read 2 more answers